General PrinciplesApril 18, 20268 min readUpdated September 30, 2026

Zero-Order vs First-Order Elimination: Graphs & PEA Drugs

First-order means percent per time, so levels fall in a curve with a constant half-life. Zero-order means amount per time; think PEA and overdose risk.

First-order elimination removes a constant fraction of the drug per unit time: the rate is proportional to concentration, the half-life is constant, and the concentration falls along a curve. Zero-order elimination removes a constant amount per unit time: the rate is fixed at the enzyme's maximum, there is no constant half-life, and the concentration falls in a straight line. Most drugs are first-order at therapeutic doses. The classic zero-order exceptions are phenytoin, ethanol and high-dose aspirin (PEA), whose metabolizing enzymes saturate. Phenytoin follows Michaelis-Menten (saturation) kinetics: its liver metabolism saturates at high levels, so once levels reach the upper therapeutic range a small dose increase can produce a large jump in its level.

The visual hack: ruler vs ski slope

Picture two graphs of plasma concentration against time.

  • Zero-order = ruler. On ordinary (linear) axes the concentration falls along a straight line, like a ruler laid on a slope: the same number of milligrams disappears every hour.
  • First-order = ski slope. On linear axes the curve is steep at first and flattens out: the same percentage disappears every hour, so less and less is removed as the level falls.
  • Flip to a semilog plot (log of concentration on the y-axis) and the pictures swap: first-order becomes the straight line, and zero-order curves downward ever more steeply.

The one-line rule: straight on normal paper = zero-order; straight on log paper = first-order.

Merck's example makes it concrete. Start with 500 mg in the body:

TimeFirst-order (half-life 1 hour)Zero-order (50 mg/hour maximum)
0 h500 mg500 mg
1 h250 mg (50% gone)450 mg (50 mg gone)
2 h125 mg (50% of what was left)400 mg (another 50 mg)
3 h62.5 mg350 mg

Side-by-side comparison

FeatureFirst-orderZero-order
Removed per unit timeConstant fraction (percent per hour)Constant amount (mg per hour)
Rate vs concentrationProportional: rate = k⋅Ck \cdot CIndependent: rate = k0k_0 (the enzyme's VmaxV_{max})
Linear-axis graphCurved (exponential decay)Straight line
Semilog graphStraight lineCurves downward
Half-lifeConstantNot constant: longer at higher levels
Clearance (rate ÷ concentration)ConstantFalls as the concentration rises
Enzyme sitesMostly freeSaturated
ExamplesMost drugs at therapeutic dosesPEA: phenytoin, ethanol, high-dose aspirin
Clinical riskPredictable dose-level relationshipSmall dose increases, big level jumps

The equations (and why half-life behaves differently)

First-order: the rate depends on how much drug is left.

dCdt=−kC⟹Ct=C0 e−kt⟹ln⁡Ct=ln⁡C0−kt\frac{dC}{dt} = -kC \quad\Longrightarrow\quad C_t = C_0\,e^{-kt} \quad\Longrightarrow\quad \ln C_t = \ln C_0 - kt

The last form is why first-order data make a straight line on a semilog plot. Setting Ct=C0/2C_t = C_0/2 gives a half-life that does not depend on concentration:

t1/2=ln⁡2k=0.693k,k=CLVd  ⟹  t1/2=0.693×VdCLt_{1/2} = \frac{\ln 2}{k} = \frac{0.693}{k}, \qquad k = \frac{CL}{V_d} \;\Longrightarrow\; t_{1/2} = \frac{0.693 \times V_d}{CL}

After nn half-lives the fraction left is (1/2)n(1/2)^n: about 6% after 4 half-lives and 3% after 5. That is the math behind the "4 to 5 half-lives" rule for washout and for reaching steady state, covered in the half-life and steady state rule.

Zero-order: the rate is a constant, so concentration falls linearly.

dCdt=−k0⟹Ct=C0−k0t⟹t1/2=C02k0\frac{dC}{dt} = -k_0 \quad\Longrightarrow\quad C_t = C_0 - k_0 t \quad\Longrightarrow\quad t_{1/2} = \frac{C_0}{2k_0}

The "half-life" is proportional to the starting concentration: the higher the level, the longer it takes to halve. That is why a zero-order drug has no single half-life, and why the Merck formula t1/2=0.693/kt_{1/2} = 0.693/k applies to first-order elimination only.

Why saturation switches the order: Michaelis-Menten kinetics

Enzymatic elimination follows the Michaelis-Menten equation:

v=Vmax CKm+Cv = \frac{V_{max}\, C}{K_m + C}

  • When C≪KmC \ll K_m: v≈(Vmax/Km) Cv \approx (V_{max}/K_m)\,C. The rate is proportional to concentration, so elimination is first-order. At therapeutic levels of most drugs only a small fraction of enzyme sites is occupied, which is why most drugs sit here.
  • When C≫KmC \gg K_m: v≈Vmaxv \approx V_{max}. The enzyme is saturated and the rate stops rising, so elimination is zero-order.
  • KmK_m is the concentration at which the rate is half of VmaxV_{max}.

So a "zero-order drug" is one whose usual concentrations are high relative to its KmK_m, so the enzyme runs near VmaxV_{max}. As a drug's concentration rises, its metabolism shifts from first-order toward zero-order. The same VmaxV_{max} and KmK_m define enzyme inhibition graphs in the Lineweaver-Burk plot guide.

PEA: the classic zero-order drugs

Mnemonic: PEA, because a pea is round like the 0 in zero-order.

DrugWhat saturatesExam-relevant facts
PhenytoinHepatic hydroxylation, mainly CYP2C9 (also CYP2C19)Target total level 10–20 mcg/mL. Per the label, nystagmus usually appears at about 20 mcg/mL, ataxia at 30 and dysarthria and lethargy above 40. Average half-life 22 hours (range 7–42), and it lengthens as levels rise
EthanolAlcohol dehydrogenase, whose KmK_m for ethanol is low (about 1 mM)Saturated at low alcohol concentrations, so over most of the intoxicating range ethanol is removed at a roughly constant rate. At very low levels the enzyme is no longer saturated and elimination follows Michaelis-Menten kinetics
Aspirin (salicylates)Hepatic metabolic pathwaysFirst-order at usual doses; the pathways saturate at high levels, giving zero-order elimination. In overdose, urine alkalinization increases salicylate excretion

Phenytoin is also a classic CYP450 inducer; see the CYP450 inducers and inhibitors list.

Phenytoin: saturation kinetics with numbers

At steady state, the daily dose (RR) equals the elimination rate, so rearranging the Michaelis-Menten equation gives:

Css=Km⋅RVmax−RC_{ss} = \frac{K_m \cdot R}{V_{max} - R}

As the dose approaches VmaxV_{max}, the denominator shrinks toward zero and the level climbs steeply. If the dose reaches VmaxV_{max}, there is no steady state: the level keeps rising. Illustrative numbers for a hypothetical patient (not reference values; bioavailability and salt form ignored) with VmaxV_{max} = 500 mg/day and KmK_m = 4 mg/L (4 mcg/mL):

Daily doseChangePredicted steady-state level (illustrative)
300 mgStart6 mcg/mL (below target)
400 mg+33%16 mcg/mL (in range)
450 mg+12.5%36 mcg/mL (ataxia range)

A first-order drug would have risen in proportion to the dose (6 → 8 → 9). This is why the Dilantin label warns that "small incremental doses may increase the half-life and produce very substantial increases in serum levels, when these are in the upper range," that a dose increase of 10% or more can disproportionately raise the steady-state level, and that dose changes should be at least 7–10 days apart.

Exam traps

  • "Constant half-life" always means first-order. A zero-order drug has no single half-life.
  • The direction of the switch: zero-order at high concentrations, first-order at low concentrations, never the reverse.
  • Aspirin is first-order at usual doses; it becomes zero-order only when its pathways saturate at high doses.
  • Zero-order does not mean "no elimination." It means a fixed amount per hour, however high the level.
  • Clearance is not constant in zero-order kinetics: with a fixed rate, clearance (rate ÷ concentration) falls as the level rises.

Practice question

A 43-year-old man with alcohol use disorder is brought to the emergency department after drinking heavily at a party. He is drowsy but protecting his airway, and his vital signs are stable. Serum ethanol levels are drawn every 2 hours while he is observed. Each level is lower than the last by the same number of mg/dL, and a plot of concentration against time on standard (linear) axes is a straight line. Which of the following best describes the elimination of ethanol in this patient?

  • A. Clearance is constant across all plasma concentrations
  • B. A constant fraction of the ethanol is eliminated per unit time
  • C. A constant amount is eliminated per unit time because alcohol dehydrogenase is saturated
  • D. The half-life lengthens as the ethanol concentration falls
  • E. Elimination is first-order at these concentrations and becomes zero-order as levels fall

Answer: C. A straight-line fall on linear axes means the same amount is removed each hour: zero-order elimination. Alcohol dehydrogenase has a low KmK_m for ethanol, so it is saturated at intoxicating concentrations and works at VmaxV_{max} regardless of how much alcohol is present.

Why the others are wrong:

  • A: Constant clearance is a first-order property. When the rate is fixed, clearance (rate ÷ concentration) is lowest at the highest levels and rises as the level falls.
  • B: A constant fraction per unit time is the definition of first-order elimination, which gives a curve on linear axes and a straight line only on a semilog plot.
  • D: This is backwards. With a fixed amount removed per hour, the time needed to halve the level (C0/(2k0)C_0/(2k_0)) gets shorter as the level falls; the half-life lengthens as levels rise, as with phenytoin.
  • E: The switch runs the other way: saturable drugs are zero-order at high concentrations and approach first-order once levels fall below saturation.

Key takeaways

  • First-order: constant fraction per unit time, rate proportional to concentration, constant half-life (t1/2=0.693/kt_{1/2} = 0.693/k), curved on linear axes and straight on semilog axes. Most drugs.
  • Zero-order: constant amount per unit time, fixed rate at VmaxV_{max}, no constant half-life, straight line on linear axes.
  • Michaelis-Menten: first-order when C≪KmC \ll K_m, zero-order when C≫KmC \gg K_m; saturation drives the switch.
  • PEA = phenytoin, ethanol, high-dose aspirin.
  • Phenytoin: small dose increases can cause disproportionate rises in level; watch for nystagmus and ataxia, and change doses no more often than every 7–10 days.
  • Ethanol: alcohol dehydrogenase saturates at low concentrations, so alcohol is removed at a roughly constant rate.

Sources

Frequently Asked Questions

What is the difference between zero-order and first-order elimination?

First-order elimination removes a constant fraction of the drug per unit time, so the rate is proportional to concentration and the half-life is constant. Zero-order elimination removes a constant amount per unit time because the eliminating enzymes are saturated, so the rate is fixed and there is no constant half-life. Most drugs are first-order at therapeutic doses.

Which drugs follow zero-order kinetics?

The classic examples are phenytoin, ethanol and aspirin at high doses, remembered as PEA. Their metabolizing enzymes saturate, so elimination proceeds at a maximal, fixed rate. Aspirin is first-order at usual doses and becomes zero-order only when its pathways saturate, as in overdose.

Why does enzyme saturation cause zero-order elimination?

Enzymatic elimination follows the Michaelis-Menten equation. When the drug concentration is far below Km, the rate rises in proportion to concentration, which is first-order elimination. When the concentration is far above Km, nearly every enzyme site is occupied, the rate is capped at Vmax and a fixed amount is removed per unit time, which is zero-order elimination.

How do you tell zero-order from first-order elimination on a graph?

On ordinary linear axes, zero-order elimination is a straight line sloping down, while first-order elimination is a curve that flattens over time. On a semilog plot the pattern flips: first-order becomes a straight line and zero-order curves downward. A straight line on a linear plot therefore means zero-order kinetics.

Is the half-life constant in zero-order kinetics?

No. With a fixed amount removed per unit time, the time to halve the level equals the starting concentration divided by twice the rate constant, so it is longer at high levels and shorter at low levels. Only first-order elimination has a constant half-life, calculated as 0.693 divided by the elimination rate constant.

Why is phenytoin dosing so tricky?

Phenytoin is hydroxylated in the liver by an enzyme system that saturates at high serum levels, so near the upper therapeutic range small dose increases can raise the half-life and the serum level disproportionately. The label warns that a dose increase of 10 percent or more can cause intoxication, with nystagmus around 20 mcg/mL and ataxia around 30 mcg/mL. Dose changes are made in small steps, at least 7 to 10 days apart.

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